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On September 22nd, 2009 01:05 a visitor came here looking for "philips 60pw9363 convergence parts" and that person was viewing the following page:
Philips LCD HDTV Reviews
After Firmware Upgrade - A Fine Small LCD TV for the Price After my previous 13 inch Sharp LCD TV died recently, I was in the market for a new small LCD TV for the kitchen. After shopping around I purchased t ...
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Question : Test for Convergence using comparison rule
(X2-1) (X7+1)dx and the domain is to 2 for the integrationI tried integrating by parts to simplify the thing to make a comparison and it just comes out way too difficult.Also, i know the answer to the limit is 0. Just dont know how to get there.
Answer:
(x2 - 1)/(x7 + 1)dx What to think about when approaching is what this function is like. The top is *like* x2, the bottom is *like* (x7), which is the same as (x7)(1/2), which is the same as x(7/2).This makes the function *like* (x2)/x(7/2), which reduces as x(2 - (7/2)), or x(4/2 - 7/2), or x(-3/2). From 2 to infinity, (x(-3/2) dx) converges. (Any negative power for n, of xn, which is less than -1, converges).Since we know it converges, we want to find a function which it is smaller than, that converges. Follow this inequality flow:(x2 - 1)/(x7 + 1)If we remove that (-1) from the numerator, it becomes smaller.(x2 - 1)/(x7 + 1) < (x2)/(x7 + 1)And if we decrease the denominator, the expression also gets smaller. By removing the +1, the expression gets smaller.(x2)/(x7 + 1) < (x2)/(x7)Which, as indicated above, reduces asx(-3/2).To recap:(x2 - 1)/(x7 + 1) < (x2)/(x7 + 1) < (x2)/(x7) = x(-3/2)So if we can prove that x(-3/2) converges, then (x2 - 1)/(x7 + 1) converges too. Integrating it:(2 to infinity, x(-3/2) dx )Which we write as a limit,lim (2 to t, x(-3/2) dx )t -> infinityWhich we use the reverse power rule to solve,lim ( (-2)x(-1/2) ) evaluated from 2 to tt -> infinitylim ( (-2)t(-1/2) - (-2)(2)(-1/2) ) t -> infinityAs t approaches infinity, t(-1/2) = 1/t(1/2) approaches zero. Evaluating the limit directly gives us (-2)(0)(-1/2) - (-2)(2)(-1/2) -(-2)(2)(-1/2) (2)*(2)(-1/2)2(1/2)sqrt(2)Since (2 to infinity, x(-3/2) dx ) converges, (x2 - 1)/(x7 + 1)dx converges too.The comparison theorem does not actually solve the limit; it only tells you that an improper integral converges. To actually solve the limit would mean to solve the integral.
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Question : Mitsubishi Big Screen TV Convergence Repair
A friend of mine is selling a Mitsubishi 61" Rear Projection T.V. Medallion HD1080 series model #WS-65819. The TV does work but he says it needs convergence repaired. Supposedly parts cost only $15 and it's not too hard to do yourself. I have done some work on electronics and know how to solder. He is selling the TV for $80. Does this sound like a good deal Thanks
Answer:
A friend of mine is selling a Mitsubishi 61" Rear Projection T.V. Medallion HD1080 series model #WS-65819. The TV does work but he says it needs convergence repaired. Supposedly parts cost only $15 and it's not too hard to do yourself. I have done some work on electronics and know how to solder. He is selling the TV for $80. Does this sound like a good deal Thanks
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